Question

i need an algebraic equation with only one variable for the following word problem: A jar contains $18.50 in dimes and quarters. There are 110 coins in the jar. How many dimes and quarters are there?

Answer 1

where x=number of quarters, and 110-x=number of dimes (because the number of dimes is 110 minus the number of quarters):

.25(x) + .10(110-x) = 18.50
.25x + 11 - .10x = 18.50
.25x - .10x = 7.50
.15x = 7.50
x = 50

50 quarters, 60 dimes

Answer 2

Oh my. That makes sense, thank you (: