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Solve for t: xf = xi + at^2
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at^2=xf-xi t^2=(xf-xi)/a t=sqrt ((xf-xi)/a)
dont forget give sign +- in front sqrt @stgreen
dude time can never be negative.....common sense
^ @RadEn
why not, if u square it u will back to the original problem :p
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lol have you ever talked like "-4 mins"??
and do u agree like this : x^-4=0 so, x=+-2, it means x satisfies for x=-2 or x=2
x^2-4=0 i meant :)
but TIME is nver negative na.....clocks don't go back....
Thanks for making it easy. I was stuck on the 2nd step for a minute there
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