Question

13r^-4(r^-5)^5/8(r^2)^-2 solve with steps please.

Answer 1

\[\frac{ 13r ^{-4}(r ^{-5})^{5} }{ 8(r ^{2})^{-2} }\]

Answer 2

\[\frac{ 13*\frac{ 1 }{ r ^{4} } (\frac{ 1 }{ r ^{5} })^{5} }{ 8*\frac{ 1 }{ (r ^{2})^{2} } }\]
Do you know how to do that?

Answer 3

Not really... can you explain please?

Answer 4

\[r ^{-100} = \frac{ 1 }{ r ^{100} }\]
Is that clear?

Answer 5

\[r ^{-4} = \frac{ 1 }{ r ^{4} }\]

Answer 6

So now you have to simplify it
\[\frac{ 13 *\frac{ 1 }{ r ^{4} * r ^{25} } }{ 8 * \frac{ 1 }{ r ^{4} } }\]
25 because 5*5 = 25

\[\frac{ 13*\frac{ 1 }{ r ^{29} } }{ 8 * \frac{ 1 }{ r ^{4} } }\]

\[\frac{ \frac{ 13 }{ r ^{29} } }{ \frac{ 8 }{ r ^{4} } }\]
(very up number is 13, hard to read)

\[\frac{ 13 * r ^{4} }{ 8 * r ^{29} }\]

29-4=25

\[\frac{ 13 }{ 8r ^{25} }\]
That should be resoult :)

Answer 7

ah, perfect! thank you so much i was struggling with problems like these thanks got it :)

Answer 8

Nice to hear that! Good luck!