Question

Need help please with Algebra 1 (rate of change)!!! Find the rate of change for each table, equation, or graph. How did you find the rate of change?

Answer 1

If there is any way you can help me? I will become a fan :)

Answer 2

\[\frac{ y2 - y1 }{ x2 - x1 } = rate of change\]

Answer 3

for a?

Answer 4

yes

Answer 5

Oh okay got it. What about option b?

Answer 6

for A is \[\frac{ 20-10 }{ 4-2 } = \frac{10}{2} = 5, \frac{30-20}{6-4} = \frac{10}{2} = 5\] so rate of change is 5.

Answer 7

Oh ok I understand. but how did you find it?

Answer 8

the formula i posted first y2 - y1/ x2- x1

Answer 9

Oh.. Oh ok got it. Thank you so much!

Answer 10

what about b?

Answer 11

change to linear form y = mx + b,\[5x+3y=-2 \to 3y = -5x-2\] then divide by 3 to get Y alone.\[y = \frac{-5x}{3}-\frac{2}{3}\] the slope is m which in this case is -5/3

Answer 12

so the rate of change is -5/3

Answer 13

Thanks. now one I totally don't get is c :/

Answer 14

well assuming the top point in the graph is 50, just use the same steps as in A, pick two ordered pairs on the graph such as (3,25) and (6, 50) then use the same formula i posted first and that's your rate of change between those two ordered pairs.

Answer 15

is (3,25) and (6,50) from the equation?

Answer 16

no they are ordered pairs you pick from the graph in C. I just picked two.

Answer 17

Oh ok

Answer 18

in task 2 for a, m = y2-y1 / x2 - x1 and use the point slope form of y - y1 = m(x - x1)

Answer 19

think u can do the rest...