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Evaluate sin 60° without using a calculator by using ratios in a reference triangle.
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form a right triangle with sides a, b and c so that the hypotenuse (c) is length 2; |dw:1354753411253:dw| we fill in the triangle this way because we know that \[a ^{2}+b ^{2}=c ^{2}\] now, sin 60º=(opposite side of the triangle)/(hypotenuse) = (sqrt3/2) (this can also be shown by using a right triangle drawn on the unit circle and then multiplying all sides by 2)
so sqrt 3/2 is equal to sin 60degrees
yes, (sqrt3)/2
okay thank you very much ryclark
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