Question

solve for x: (4x-3)^2=-15

Answer 1

so (4x-3)^2=(4x-3)(4x-3) right

Answer 2

yes

Answer 3

so take that and foil it

Answer 4

(4x-3)(4x-3) = 4x(4x - 3) - 3(4x - 3) = 16x^2 - 12x - 12x +9 = 16x^2 - 24x + 9

Answer 5

16x^2-24x+24=0

Answer 6

but its not = to 0 its =-15

Answer 7

(4x-3)(4x-3)
= 4x(4x - 3) - 3(4x - 3)
= 16x^2 - 12x - 12x +9
= 16x^2 - 24x + 9

Answer 8

my bad see you already did that

Answer 9

so now is there a common number that they are all divisible by?

Answer 10

wait im at 16x^2-24x+9=-15 right?

Answer 11

ya then add the 15 to get 16x^2-24x+24=0

Answer 12

okay yeah i did that

Answer 13

now find a common denominator

Answer 14

8?

Answer 15

yup

Answer 16

so does that then turn into 2x^2-3x=3=0?

Answer 17

2x^2-3x+3 sorry

Answer 18

16x^2-24x+9=-15
16x^2 - 24x + 24 = 0
8(2x^2 - 3x + 3) = 0
2x^2 - 3x + 3 = 0
x^2 - 3/2 + 3/2 = 0
x^2 - 3/2x = -3/2
x^2 -3/2x + 9/16 = -3/2 + 9/16
(x - 3/4)^2 = -15/16

Solution is imaginary

Answer 19

yes

Answer 20

then what do i do?

Answer 21

the answer is 3 + or - the square root of 15 divided by4 but idk how to get it

Answer 22

i would do the quadratic formula

Answer 23

-b + or - the square root of b^2 -4ac divided by 2a?

Answer 24

\[\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]

Answer 25

(-b+-sqrt(b^2-4ac))/2a

Answer 26

yup

Answer 27

i got it thanks to both of you!

Answer 28

not a problem

Answer 29

You got what? Mind sharing what you got?

Answer 30

3 + or - the square root of 15 divided by 4

Answer 31

3+ or - i square root 15 divided by 4 sorry i forgot the "i"

Answer 32

yup