what is the slope of the line that is perpendicular to the line that passes through the points (7,6) and (3,-4)
first you want to find the slope of those points
so how would i do that?
(y2-y1)/(x2-x1)
ok give me a sec
sure
okay I got 2.5
next you put it into point slope form or (y-y1)=m(x-x1)
i dont know how to do that
well you found your slope m and pick one of your sets of points and plug them in for y1 and x1
okay i got -2/5 for an answer, is that correct?
y-6=2.5(x-7)
no, @katlin95, slope of the perpendicular line to a line with slope m is -1/m ...leave your slope in fraction form and see what -1/m = ?
hhhm this is hard for me lol
y-6=(1/2.5)x-((1/2.5)*7)
@katlin95, once you get slope m which you already found, just find what -1/m is :) that isn't hard is it?
the question ask for slope of perpendicular line, nickr is finding the equation, not the slope
oh all you need is the slope my bad, didnt see that
nice catch
@nickr np :) enjoy the night
thanks same to you
-2??? right?
no your slope is 2.5 so your answer would be 1/2.5
your slope m is 10/4 = 5/2 ...so -1/m = -1/(5/2) = -2//5 don't write slope in decimal ...leave it as fraction, will make it much easier for you
and thanks nick :)
i dont have that as an answer all i got was -2/5 for answer, which i said long before as my first answer
thanks so much guys!
yes you are correct trying to type to fast and forgot negative
np sorry i messed up
we all make mistake:)
nickr, don't you worry, i made mistakes all the time :)
what now you dont lol
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