Question

use dy to estimate change of y when x changes are indicated:
y=x^3 from x=4 to x=4.02

Answer 1

\[dy=3x ^{2}dx\]
\[dy=3\times16\times (0.2)^{2}\]

Answer 2

how did you get 3×16? I know that its f(a) x f'(a) x (x-a), but I don't see how you got f(a) and f'(a)

Answer 3

dy=0.96

Answer 4

the point where you evaluate the function dy is x=4

dx=(4-4.02)=0.2 not squared is a error

Answer 5

I am using the derivative of y=x**2 that is dy/dx=3x**2