Question

HELP!!
(2x-1)(3x+4)(4-2x)
SHOW STEPS PLEASE :)

Answer 1

Ok, for this problem first you need to multiply out all the parenthesis. You can start by doing (2x-1) x (3x+4), which equals\[6x ^{2}+8x-3x-4\]

Answer 2

ok.....and for the last

Answer 3

Then you'll want to multiply that product by your last set of parenthesis, (4-2x). That ends up equaling \[-12x ^{3}+20x ^{2}+28x-16\]

Answer 4

Do you need to solve for x or are you only simplifying?
Also, do you understand how I got what I got?

Answer 5

yes and yes

Answer 6

Ok, to solve for x you need to set the entire equation equal to zero.
I'm honestly really sketchy on the details of how to solve cubic equations and I don't want to give the wrong answer, but this website should help you out:
http://www.1728.org/cubic.htm

Answer 7

6x^2+8x-3x-4 should be multiplied by (4-2x)