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Find the equation of the circle with center (4,3) that passes through the point (0,0)
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i think it's (x-4)^2 + (y-3) ^2 = 25
how did u get the 25 though I got the same (x-4)^2 + (y-3)^2 = ?
the radius is 5.
draw a line from the point to the origin
and you will see the x axis is 4 units long, y is 3 units long. so you have a right triangle
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so the hypotenuse is 5, or the radius is 5. so you square 5 and get 25
ooo thats so cool and great! Thank you. Is there anyway you can do that without having to draw it out like would I just automatically plug in the center pair into the Pythagorean theorem?
if the circle passes through the origin, then you can use pythrogren, otherwise, drawing it is better
o ok thank you very much!
you're welcome!
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