Find the equation of the circle with center (4,3)
that passes through the point (0,0)

Question

Find the equation of the circle with center (4,3)
that passes through the point (0,0)

anonymous · Answer

i think it's (x-4)^2 + (y-3) ^2 = 25

anonymous · Answer

how did u get the 25 though
I got the same  (x-4)^2  + (y-3)^2 = ?

anonymous · Answer

the radius is 5.

anonymous · Answer

draw a line from the point to the origin

anonymous · Answer

and you will see the x axis is 4 units long, y is 3 units long. so you have a right triangle

anonymous · Answer

so the hypotenuse is 5, or the radius is 5. so you square 5 and get 25

anonymous · Answer

ooo thats so cool and great! Thank you. Is there anyway you can do that without having to draw it out like would I just automatically plug in the center pair into the Pythagorean theorem?

anonymous · Answer

if the circle passes through the origin, then you can use pythrogren, otherwise, drawing it is better

anonymous · Answer

o ok thank you very much!

anonymous · Answer

you're welcome!