Question

find a cartesian cuestion r=2cos(theta) + 3sin(theta)

Answer 1

x/r = cos(theta)
y/r = sin(theta)
r^2 = x^2 +y^2
have you made those substitutions?

Answer 2

help me you please.... with this

Answer 3

make those substitutions... tell me what you get...

Answer 4

r= 2x/r + 3 y/r ...........> r2=2x+2y .. ...............> x2 + y2= 2x + 3y ------> x2-2x-3y+y2= 0... is it correct¿?

Answer 5

yes

Answer 6

you can clean it up a bit by completing the square on both the x and y terms..
eg.:
(x^2 -2x) = (x^2 -2x +1) -1
= (x-1)^2 -1

Answer 7

what is the best¿?

Answer 8

what?

Answer 9

ok ok thanks .... can you help with other¿?

Answer 10

xy=8

Answer 11

just sub.s in x=rcos(theta), y=rsin(theta)

Answer 12

rcostheta + rsintheta = 8 ¿?