Mathematics
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OpenStudy (anonymous):
http://media01.owotw.com/o_alg02_2011/7/q1p14.gif
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OpenStudy (anonymous):
@jim_thompson5910 help i need the answer please
jimthompson5910 (jim_thompson5910):
how can you simplify \[\Large \sqrt{20}\]
OpenStudy (anonymous):
Combine and simplify the following radical expression.
jimthompson5910 (jim_thompson5910):
can you factor 20 into two numbers where one of them is a perfect square?
OpenStudy (anonymous):
2root 5
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OpenStudy (anonymous):
@iiforgot
jimthompson5910 (jim_thompson5910):
yep, \[\Large \sqrt{20} = 2\sqrt{5}\]
jimthompson5910 (jim_thompson5910):
do the same with the other roots
jimthompson5910 (jim_thompson5910):
then combine like terms
OpenStudy (anonymous):
root 45 answer is 3root five
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jimthompson5910 (jim_thompson5910):
keep going
OpenStudy (anonymous):
root 80 answer is 4 root 5 but do not combine like terms help
jimthompson5910 (jim_thompson5910):
so you have
sqrt(20) = 2*sqrt(5)
sqrt(45) = 3*sqrt(5)
sqrt(80) = 4*sqrt(5)
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
but i need the answer please
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jimthompson5910 (jim_thompson5910):
multiply then combine like terms
think of something like
2*sqrt(5) + 3*sqrt(5) as 2z + 3z
OpenStudy (anonymous):
so bad to multiply
jimthompson5910 (jim_thompson5910):
\[\Large 2\sqrt{20} + 8\sqrt{45} - \sqrt{80}\]
\[\Large 2*2\sqrt{5} + 8*3\sqrt{5} - 4*\sqrt{5}\]
\[\Large 4\sqrt{5} + 24\sqrt{5} - 4*\sqrt{5}\]
\[\Large (4 + 24 - 4)*\sqrt{5}\]
\[\Large 24\sqrt{5}\]
jimthompson5910 (jim_thompson5910):
So
\[\Large 2\sqrt{20} + 8\sqrt{45} - \sqrt{80} = 24\sqrt{5}\]