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Mathematics 4 Online
OpenStudy (anonymous):

consider the word PEPPERCORN a.how many different strings can be made from this word when all letters are used b.how many different start and end with p c.in how many strings are the 3 letters P consecutive

OpenStudy (anonymous):

if the letters were all different it would be \(10!\) but since you cannot tell the 3 Ps apart, or the 2 Es or the 2 Rs it is \[\frac{10!}{3!2!2!}\]

OpenStudy (anonymous):

why divide and not subtract

OpenStudy (anonymous):

good question

OpenStudy (anonymous):

it is the counting principle since you cannot tell the 3 Ps apart, for example, when you compute 10! you have over-counted by the number of ways you can permute the 3 P's there are 3!=6 ways but that doen't mean you counted 6 extra ways, it means you over-counted by a factor of 6

OpenStudy (anonymous):

Ahh thnx :D

OpenStudy (anonymous):

can you please answer part B and C?

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