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What is the equation of y = x^3 with the given transformations? vertical stretch by a factor of 3, horizontal shift 4 units to the right, vertical shift 3 units down
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Y=3(x-4)^3 -3
let f(x) = x^3 so with those transformations, your graph will be: y = 3f(x-4) + 3
Hmm which one of you is right? xD
mine
see vertex will be at x=4 and that is suppose to be -3
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Okay thanks so much!
were both right.... my answer is in terms of the transforms given... the other answer is the simplified form....
when ever shifting is done we wright (y-k)=f(X-h)
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