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Mathematics 6 Online
OpenStudy (anonymous):

Help, please?

jimthompson5910 (jim_thompson5910):

hint |dw:1354870793014:dw| the largest angle is opposite the largest side the smallest angle is opposite the smallest side

OpenStudy (calculusfunctions):

What Jim said plus I will add the fact that THE SUM OF THE LENGTHS OF ANY TWO SIDES OF A TRIANGLE IS GREATER THAN THE LENGTH OF THIRD SIDE.

jimthompson5910 (jim_thompson5910):

name the largest angle

OpenStudy (calculusfunctions):

Yes so then which is the largest side? side a, b, or c?

jimthompson5910 (jim_thompson5910):

|dw:1354871339016:dw|

jimthompson5910 (jim_thompson5910):

side a is largest (since it's opposite the largest angle A)

jimthompson5910 (jim_thompson5910):

so if you meant 'a' or segment BC, then you are correct

jimthompson5910 (jim_thompson5910):

so BC is the longest side

jimthompson5910 (jim_thompson5910):

no, I is false from what calculusfunctions wrote above

jimthompson5910 (jim_thompson5910):

if it were AC + AB > BC then it would be true

jimthompson5910 (jim_thompson5910):

by last one you mean III or the line that says "I, II, and III" ??

jimthompson5910 (jim_thompson5910):

it can't be AC + AB = BC because if this was true, then you'd have a straight line that would look like this |dw:1354871690167:dw|

jimthompson5910 (jim_thompson5910):

so a triangle isn't even possible if AC + AB = BC

jimthompson5910 (jim_thompson5910):

that view is a blown up view of a sandwiched/glued together line segments btw

jimthompson5910 (jim_thompson5910):

yes, II is only thing true

jimthompson5910 (jim_thompson5910):

whoa...where did your question go?

jimthompson5910 (jim_thompson5910):

yw

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