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Solve 2sin2A = 1 for 0º≤A≤360º
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start by dividing by 2. That way you get \[\sin 2A=\frac{ 1 }{ 2 }\] Now, which radians give you sin=1/2?
2sin^2A = 1, the sin^2 is what im confused by.
\[\sin ^{2}??\]
yesum.
is the original equation squared?
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2sin^2A = 1, that's the original equation.
oohhh ok. lemme rewrite that
it would be: \[\sin ^{2}A=\frac{ 1 }{ 2 }\]
ok, how I learned it, solve for A as if it were not squared. Simply, ignore the squared until the end. Now, what gives you what value (in radians? gives you 1/2?
that doesn't fit into the answers is the only problem
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wait! I just saw my mistake.
|dw:1354922611152:dw|
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