Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (dls):

find derivativeof e^xy+xy=0

OpenStudy (dls):

\[e^{xy} +xy=0\]

OpenStudy (anonymous):

what about it

OpenStudy (dls):

@zepdrix

OpenStudy (anonymous):

wrt to what?

OpenStudy (dls):

dy/dx

zepdrix (zepdrix):

:o

OpenStudy (dls):

O_o

zepdrix (zepdrix):

\[\huge e^{xy}(xy)'+(x)'y+x(y)'=0\]Which part you getting stuck on? :D Looks like we have the product rule a few times.

OpenStudy (dls):

I know e^x=e^x itself but e^xy too?

zepdrix (zepdrix):

\[\huge (e^{\text{potato}})'=e^{\text{potato}}(\text{potato})'\]Yup the thing in the exponent doesn't change :D You just need to apply the chain rule.

OpenStudy (dls):

okay! thanks :")

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
2 days ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
2 days ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!