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find derivativeof e^xy+xy=0
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\[e^{xy} +xy=0\]
what about it
@zepdrix
wrt to what?
dy/dx
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:o
O_o
\[\huge e^{xy}(xy)'+(x)'y+x(y)'=0\]Which part you getting stuck on? :D Looks like we have the product rule a few times.
I know e^x=e^x itself but e^xy too?
\[\huge (e^{\text{potato}})'=e^{\text{potato}}(\text{potato})'\]Yup the thing in the exponent doesn't change :D You just need to apply the chain rule.
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okay! thanks :")
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