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Solve each of the following by using the quadratic formula.
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1) x2 - 3x + 2 = 0
\[x=\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]For you, a=1, b=-3, and c=2. It's just plug-and-chug.
Remember the formula of a polynomial: \[ax ^{2}+bx+c\]
when do I put the square root on windows calculator?
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is that how you do it? I havent put the sq root, do I do it seperate or together?
Well, the stuff under the square root is: 1\[(-3)^{2}-4 \times 1 \times 2=1\], and the square root of 1 is just 1. So then you just have\[\frac{ 3+1 }{ 2 }\]and\[\frac{ 3-1 }{ 2 }\]
so you used -3 as 3 to solve x
I guess I get it now thanks
Well, it's -b, and since b is -3, -(-3) is just 3.
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