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How do you calculate the derivative of this function?
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\[\sqrt{x} + 1\]
make it to a fractional exponent - so it's x^(1/2)+1
the derivative is 1/(2√x)
Can you explain how exactly you got the derivative?
Ok. So you get the exponent of the term. Put it in the front of the term. Then take the exponent again and subtract it by 1. That becomes your new exponent.
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so in this case, you have the exponent of 1/2. You pull the in the font of your term. Now, you subtract 1. That becomes -1/2. That means 1/√x.
Derivative of a constant is 0, so the 1 becomes a 0
questions?
Ahhhhhhhhhh!
I get it! Thank you so much!
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You are welcome!
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