Question

a parabola with a vertex at (6,0) and passes through (5,-2)

Answer 1

could you also add the equation of the parabola in vertex and standard form

Answer 2

y = a(x - h)^2 + k

That is your general vertex equation. That is an equation with 5 variables, so at first, you might get the impression that this is impossible, but you are given 4 of the values, so you have an equation in only one variable, "a", once you substitute for h, k, x, and y.

Answer 3

Your vertex is (6, 0) which is (h, k), so h=6, and k=0.

Also, you are given point (5, -2) which is your (x, y), so x=5 and y = -2

Make those 4 substitutions and then solve for "a". Once you get "a", re-write the general equation substituting for "a", "h", and "k", and that will be your final vertex form for your equation. To get your standard form, you will have to multiply out the term with the "^2" and simplify.

Answer 4

thank you

Answer 5

You're welcome!