9.
Find all the zeroes of the equation.
x3 – x2 = –3x – 3 (1 point)

Question

9.  
Find all the zeroes of the equation.
x3 – x2 = –3x – 3  (1 point)

anonymous · Answer

$$x ^{3}-x ^{2}=-3x-3?????????$$

anonymous · Answer

Start by setting the equation equal to 0
x3 – x2 = –3x – 3
move –3x – 3 to the left side
so:
x3 – x2+3x-3=0

anonymous · Answer

So then I set those numbers equal to zero?

anonymous · Answer

Now, From x3 – x2+3x-3=0, you want to factor
So (x-1)(x^2+3)=0
(x-1)=0
(x^2+3)=0

campbell_st · Answer

slight error

the equation when set to zero is

x^3 - x^2 + 3x + 3 = 0

anonymous · Answer

oops. My bad. 
So then just factor: 
x^3 - x^2 + 3x + 3 = 0

campbell_st · Answer

so good luck finding the zeros... and I hope there is a typo... 

I think there has to be 2 complex roots at a guess

anonymous · Answer

I'm so confused :/

campbell_st · Answer

is your original equation correct... $$x^3 - x^2 = -3x - 3$$

anonymous · Answer

Yes it is.

anonymous · Answer

I dunno. I have been stuck on 2 questions for about an hour now and they should be pretty easy but they aren't. :/

anonymous · Answer

$$i \sqrt{3} , 1$$

anonymous · Answer

Would that be the zeros?

campbell_st · Answer

nope... thats why I asked if the equation was correctly typed...

anonymous · Answer

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