Question

saw

Answer 1

for \(ax^2+bx+c=0\)

the discriminant is \(\Delta = b^2-4ac\)

Answer 2

when Δ is positive there are two real solutions
when Δ is zero there is one real solution
when Δ is negative there are two complex solutions

(a complex number has a real and an imaginary part )

Answer 3

if you had to find these solutions,

then you would use quadratic formula
\[\frac{-b\pm\sqrt \Delta}{2a}\]


i guess your solutions would be purely imaginary only when \(b=0\)

Answer 4

Are you a connections student? @morganlana17