Question

Simplify. Multiply Pure Imaginary Numbers.
22.) the square root of -13 * the square root of -26.

Answer 1

sqrt(-13) = sqrt(-1*13) = sqrt(-1) sqrt(13) = i sqrt(13)
sqrt(-26) = sqrt(-1*2*13) = sqrt(-1) sqrt(2) sqrt(13) = i sqrt(2) sqrt(13)
so, multiply of them :
sqrt(-13) * sqrt(-26) = i sqrt(13) * i sqrt(2) sqrt(13)
continue it....

Answer 2

are you sure that's correct

Answer 3

yes, still incomplete :)
can u simplify it

Answer 4

Let's see stay on here for awhile not long

Answer 5

so is your work written like this: \[i \sqrt{13} * i \sqrt{2} * \sqrt{13}\]

Answer 6

yes, now simplify it ....

Answer 7

\[13i \sqrt{2}\]

Answer 8

i * i = i^1 = (sqrt(-1))^2 = -1
the rest have corrected

Answer 9

so what did I do wrong

Answer 10

i^2 i mean :)

Answer 11

cancel out i, because has be -1

Answer 12

so would it be -13

Answer 13

where's the sqrt(2) ?

Answer 14

\[-13\sqrt{2}\]

Answer 15

thats all right ^^

Answer 16

so there is no i in this problem

Answer 17

i was death :p

Answer 18

It's basically because it got cancelled out right or what

Answer 19

just understanding define of i = sqrt(-1)
so, i * i = sqrt(-1) * sqrt(-1) = {sqrt(-1)}^2 = -1
as proportion, let's we ask to the best calculator :
http://www.wolframalpha.com/input/?i=sqrt%28-13%29sqrt%28-26%29