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consider the quadratic function f(x)=-2x(squared)+12x-10 , find coordinates of the vertex:(x,y)?
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Completing the Square might be the first line of defense.
\[f(x)=-2x^2+12x-10\]first coordinate of the vertex is \(-\frac{b}{2a}\) in your example it is \[-\frac{12}{2\times (-2)}=3\]
second coordinate of the vertex is what you get when you replace \(x\) by \(3\)
Thank you for your help. I can probably figure it out from here. Thanks again.
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