Question

Given that the integral from [0,2] of f(x)dx=2, the integral from [0,3] of f(x)dx=6, and the integral from [3,6] of f(x)dx=4, find the integral from [0,6] of f(x)dx.

Answer 1

[0,3]+[3,6] = [0,6]
6+4 = 10

Answer 2

Usually I would approach this as the integral from [a,c] = the integral from [a,b] + the integral from [b,c]. But two of these integrals overlap each other, so I'm confused.

Answer 3

Oh, so the [0,2] integral is not important here?

Answer 4

yep, dont think too hard :D

Answer 5

Lol ok thanks.