If you are finding the line perpendicular to x + 3y = 5, what is the slope of the line? Answer -3/5 1/3 3 -3
find you slope first then take the opposite sign and the reciprocal of the number
What is the anwser?
so what is the slope?
gotta go, maybe someone will help you
Ok, so you need to solve for y, then do as precal said and take the opposite reciprocal meaning negative flipped fraction
so you got?
nope!
take your equation and solve for y tell me what equation you get at that point hint: y=?
No idea! I am So stupid!
Sorry, once we get down to pre-algebra stuff I forget how to teach it. :/ Best I can say is whatever you do to one side you have to do it to the other side.
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Write the slope-intercept equation of the line perpendicular to y = 5/2 x - 2, which passes though the point (0, 2). Answer y = 5x + 2 y = -2/5x + 2 y = 2x + 5 y = 1/2x + 5
the number in front of x is (-1/3) you want +3
sorry gotta go
First change it into Slope-Intercept form. y = mx + b where m is slope. x + 3y = 5 Subtract x. 3y = -x + 5 Divide by 3. y = -1/3 + 5/3 So your slope is -1/3. However it asks for the slope of the line perpendicular to this one. Slope of perpendicular lines are the opposite reciprocal - change the value from positive to negative or vice versa, then find the reciprocal. ex. opposite reciprocal of -1/2 is +2/1 or 2
So what is the opposite reciprocal of -3/1?
1/3!
Sorry I meant to say, what is the opposite reciprocal of -1/3. My mistake!
So what is the opposite reciprocal of -1/3?
I believe I stated it already +3
ohh sorry! Didn't see it. (:
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