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Mathematics 6 Online
OpenStudy (anonymous):

Find a Cartesian equation for the curve and identify it. r2 cos 2θ = 1

OpenStudy (anonymous):

so i know r^2=x^2 + y^2

OpenStudy (anonymous):

so i substituted that in and got (x^2+y^2)cos(2theta)=1

OpenStudy (anonymous):

then divided both sides by cos(2theta) x^2+y^2=sec(2theta)

OpenStudy (anonymous):

not sure what to do now

OpenStudy (anonymous):

sec(2theta) = 1/cos(2theta) = r^2 so.. x^2 +y^2=r^2.. dunno lol

OpenStudy (anonymous):

r^2cos2(theta)=1 or r^2((cos(theta))^2 - (sin(theta))^2)=1 (formula for cos2(theta)) ((r cos(theta))^2 - (r sin(theta))^2)=1 or x^2 -y^2 =1 [as x=rcos(theta) and y=r sin(theta)]

OpenStudy (anonymous):

\[\cos(2\theta)=\cos^2(\theta)-\sin^2(\theta)?\]

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