Question

Write the equation of the line that passes through (-4,12) and (7,23)
A. Y=x+16
B. y=3x+18
C. Y=1/6x+16
D. Y=1/3x+18

Answer 1

Please help I'm desperate

Answer 2

The equation is of the form y = mx + c where m is the slope. You can find the slope from
\[m=\frac{y _{1}-y _{2}}{x _{1}-x _{2}}\]
Can you do that?

Answer 3

A

Answer 4

@micahcarr76 You choice is correct.

Answer 5

The point-slope form of a line is \(y-y_1=m(x-x_1)\). You can find the slope \(m\) using:$$m=\frac{y_2-y_1}{x_2-x_1}=\frac{23-12}{7--4}=\frac{11}{11}=1$$Therefore we can simplify the above point-slope form to \(y-y_1=1(x-x_1)=y-y_1=x-x_1\). We can pick either point to plug into our template for the point-slope form so I'll do both.

Let's try \((-4,12)\), which yields:$$y-12=x--4=x+4\\y=x+4+12=x+16$$
To prove that it also works using the other point, let's try \((7,23)\):$$y-23=x-7\\y=x-7+23=x+16$$
So our answer is conclusively (A).

Answer 6

Already had the answer and was about to close the question when u guys responded