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Mathematics 19 Online
OpenStudy (anonymous):

Linearization?

OpenStudy (anonymous):

f(x) = tanx a=pi

OpenStudy (anonymous):

f'(x) = sec^2x ?

hartnn (hartnn):

the linear function y is given by y= f(a) + f'(a) (x-a) here , a =pi, f'(x) = sec^2 x whats f(a) =... ? just replace 'x' in f(x) by a =pi. whats f'(a) =... ? just replace 'x' in f'(x) by a =pi.

OpenStudy (anonymous):

f'(pi) = 1?

OpenStudy (anonymous):

f(pi) = tan(pi) = 0

OpenStudy (anonymous):

L(x) = 0+ 1(x-pi)

hartnn (hartnn):

absolutely correct!

OpenStudy (anonymous):

ohhh ok thanks!!

hartnn (hartnn):

welcome ^_^

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