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Linearization?
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f(x) = tanx a=pi
f'(x) = sec^2x ?
the linear function y is given by y= f(a) + f'(a) (x-a) here , a =pi, f'(x) = sec^2 x whats f(a) =... ? just replace 'x' in f(x) by a =pi. whats f'(a) =... ? just replace 'x' in f'(x) by a =pi.
f'(pi) = 1?
f(pi) = tan(pi) = 0
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L(x) = 0+ 1(x-pi)
absolutely correct!
ohhh ok thanks!!
welcome ^_^
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