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Mathematics 18 Online
OpenStudy (dls):

Find dy/dx

OpenStudy (dls):

\[x=3\cos \theta -\cos^{3} \theta ,y=3\sin \theta-\sin 3 \theta \]

OpenStudy (anonymous):

first do dx/dtheta then dy/dtheta then divide dx/dtheta by dy/dtheta

OpenStudy (anonymous):

Use parametric method

OpenStudy (dls):

Im not known to the parametric method yet!

OpenStudy (dls):

I want to learn about that

OpenStudy (anonymous):

k i am uploading a small theory about it give me a minute

OpenStudy (dls):

yes,thanks!

OpenStudy (anonymous):

OpenStudy (dls):

How will i find the Derivative of sin3theta?

OpenStudy (anonymous):

Do you know chain rule of differentiation

OpenStudy (dls):

yes

OpenStudy (anonymous):

chain rule will be used here

OpenStudy (dls):

will it be like this? cos3theta + 3costheta

OpenStudy (dls):

i dont know..

OpenStudy (anonymous):

No No nO no no

OpenStudy (anonymous):

i am uploading another pic

OpenStudy (dls):

\[\cos 3 \theta \times \frac {d}{d \theta} \times 3 \theta?\]

OpenStudy (callisto):

Let u=3θ \[\frac{dy}{d\theta} = \frac{dy}{du}\times\frac{du}{d\theta} = (\frac{d}{du}sinu) \times (\frac{d}{d\theta}3\theta)\]

OpenStudy (dls):

^^

OpenStudy (callisto):

\[\cos 3 \theta \times \frac {d}{d \theta}(3 \theta)\]

OpenStudy (dls):

does that mean theta is a function? O_O

OpenStudy (dls):

i thought it was a variable

OpenStudy (callisto):

Variable :S

OpenStudy (dls):

lol

OpenStudy (callisto):

Refer to the my previous post..

OpenStudy (callisto):

Not the variable one :S

OpenStudy (dls):

is it a function or not >.>

OpenStudy (anonymous):

yeah yeah

OpenStudy (anonymous):

OpenStudy (dls):

:D

OpenStudy (anonymous):

Mr. DLS i think you should review chain rule and parametric equation from the book

OpenStudy (dls):

yes..

OpenStudy (dls):

and

OpenStudy (dls):

\[3\sin \theta = 3\cos \theta+ \sin theta \]

OpenStudy (callisto):

Why?

OpenStudy (dls):

asking is it correct

OpenStudy (dls):

UV rule?

OpenStudy (anonymous):

no 3sin\[differentiation of 3sintheta=3\cos\]

OpenStudy (dls):

y not UV?

OpenStudy (anonymous):

3 is a constant and (sin) is the the only function so there we won't be applying UV rule

OpenStudy (anonymous):

UV rile is applied when twi functions are in product F=U.V U is a function , and V is another function

OpenStudy (anonymous):

*rule *two

OpenStudy (dls):

okay..tyy

OpenStudy (anonymous):

kk please practice maths daily differention and integration these two are basic blocks of maths

OpenStudy (dls):

yes..

OpenStudy (dls):

Im getting \[\LARGE \frac{dy}{dx}= \frac{3\cos \theta-3\cos3 \theta}{3 \sin \theta-3 \sin 3 \theta} \]

OpenStudy (anonymous):

OpenStudy (dls):

yes!

OpenStudy (dls):

\[x=a(cost+\log \tan \frac{t}{2})\] what do u get on finding the derivative of this? I got.. \[\frac{dx}{dt}=a(-sint+\frac{1}{2 \sqrt {\tan \frac{t}{2}}} \times \sec^2 \frac{t}{2}\] just confirming

OpenStudy (dls):

@hartnn

OpenStudy (dls):

check this answer once^^

hartnn (hartnn):

d/dx of log x is 1/x

hartnn (hartnn):

not , 1/ 2sqrt x

OpenStudy (dls):

oh yes T_T sorry

OpenStudy (dls):

rest?

hartnn (hartnn):

d/dxof tan t/2 = sec^2 t/2 * (1/2)

OpenStudy (dls):

I SEE :O thanks!

hartnn (hartnn):

\[ \begin{array}l\color{red}{\text{w}}\color{orange}{\text{e}}\color{#e6e600}{\text{l}}\color{green}{\text{c}}\color{blue}{\text{o}}\color{purple}{\text{m}}\color{purple}{\text{e}}\color{red}{\text{ }}\color{orange}{\text{^}}\color{#e6e600}{\text{_}}\color{green}{\text{^}}\color{blue}{\text{}}\end{array} \]

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