Question

Rectangle inside of a rectangle.
Inner rectangle: L=2x & W=x
There is 7 ft of space between the inner rectangle and the outer rectangle on both sides.
Outer Rectangle: L=2x+14 & W=x+14
The area of the outer rectangle is 952ft^2

My job is to find the dimensions of the inner rectangle.

Below is the work that I have so far.
My mind is not on track for some reason & I keep getting stuck.. please help.

Answer 1

(2x+14)(x+14)
2x^2+28x+14x+196
2x^2+42x+196 =952
-952 -952
2x^2+42x -756 =0??

(2x+7)(x+7) = 952
2x^2+14x+7x+49
2x^2+21x+49=952
-952
2x^2+21x -903

Answer 2

your hot

Answer 3

-_-

Answer 4

like reallllllllly

Answer 5

How can the area of both rectangles be 952 sq ft? Isn't one a lot larger than the other?

Answer 6

The smaller one is inside of the other.
That's why I put both, technically its the area of the larger one.

Answer 7

From your first equation x =\[-21\pm \sqrt{6069}\over 4\]

Answer 8

I believe it is an irrational number but real, using the positive value.