Identify the vertex and the axis of symmetry of the graph of the function y = 3(x + 2)2 – 3.

A)vertex: (2, –3);
axis of symmetry: x = 2

B)vertex: (–2, –3);
axis of symmetry: x = –2
vertex: (2, 3);

C)axis of symmetry: x = 2

D)vertex: (–2, 3);
axis of symmetry: x = –2

Question

Identify the vertex and the axis of symmetry of the graph of the function y = 3(x + 2)2 – 3.  

A)vertex: (2, –3);
axis of symmetry: x = 2

B)vertex: (–2, –3);
axis of symmetry: x = –2
vertex: (2, 3);

C)axis of symmetry: x = 2

D)vertex: (–2, 3);
axis of symmetry: x = –2

anonymous · Answer

Vertex for C was (2,3)

anonymous · Answer

I'm really confused on this

anonymous · Answer

Your equation is vertex form y=a(x-h)^2+k where (h,k) is the vertex, can you see what it is?

anonymous · Answer

No. We were never taught this stuff, but from looking at what ur saying would it be (2,-3)

anonymous · Answer

At least thats what I get from it

anonymous · Answer

Close, there's a sign change on h so its actually (-2,-3)

the axis of symmetry is just x=h so x=-2

anonymous · Answer

Thnx so much for your help