PLEASE HELP!!!

A point on the tread of a tire with a radius of 0.50 m rotates one-quarter turn, which is /2 radians. What is the linear distance of the displacement?

a. 0.32 m

b. 0.45 m

c. 0.79 m

d. 1.6 m

Question

PLEASE HELP!!!

A point on the tread of a tire with a radius of 0.50 m rotates one-quarter turn, which is /2 radians. What is the linear distance of the displacement?

a.  0.32 m

b.  0.45 m

c.  0.79 m

d. 1.6 m

agent0smith · Answer

It's a bit confusing that it asks for the "linear distance of the displacement"... but it seems like they want the distance traveled. They basically want the arc length. .

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agent0smith · Answer

Since it rotated by one quarter turn or pi/2, we can find the distance traveled in the same way you find circumference (C = 2*pi*r) except 2*pi is for a full circle, and we only have a quarter circle so we want to use pi/2

$$d=\frac{ \pi }{ 2 }r$$
and now you can find d since r is 0.5m.

anonymous · Answer

Thanx! I appreciate ur help!