Question

Prove this.

Answer 1

\[\frac{ \sin \theta \sec \theta }{ \tan \theta +\cot \theta }=\sin ^{2}\]

Answer 2

sinθsecθ = sinθ *1/cosθ = tanθ, right ?

Answer 3

Yeah, sin/cos=tan

Answer 4

so, for left side can be :
(tanθ)/(tanθ+cotθ)
multiply the fraction by tanθ/tanθ, then simplify it...

Answer 5

The tan^2 on the top and bottom cancel, and the 1/cot is the same thing as tan, right? So how does tan=sin^2 ?

Answer 6

it can be