Question

please help!? What is the vertical asymptote of y=log(x-2)+5?

Answer 1

You can't take the log of 0, so x-2 is positive (since you can't take the log of a negative either)

if the argument of the log was zero, then...

x - 2 = 0

x = 2

This value causes x-2 to be zero, which creates the vertical asymptote

So the vertical asymptote is x = 2

Answer 2

@jim_thompson5910 THANK YOU SO MUCH! you really helped me a lot :) can you help me with this one more just to be positive that i understand? i would really appreciate it! i can give you another best response? :) thanks so much anyway! What is the vertical asymptote of y=ln(x+3)+2?

Answer 3

same idea, ln is a natural log though

Answer 4

so

x+3 = 0

solve for x and whatever you get is your vertical asymptote

Answer 5

so x =-3?

Answer 6

@jim_thompson5910

Answer 7

yep

Answer 8

thanks so much again!! :)