Question

Given: cos(theta) = 3/5 and theta is located in the fourth quadrant; find sin2(theta)

Answer 1

ok sin2x has the identity
sin2x = 2sinxcosx.. know of it?

Answer 2

Yes, do I just find out what cos(theta) is & then subsitute both sin & cos? like would my equation be 2(4/5)(3/5)?

Answer 3

yes it would be something like this ..

Answer 4

Okay, I think I know how to get there. Thanks :)

Answer 5

you are most welcome :)