Question

The sum of three consecutive EVEN integers is 42. What are the integers? (Name all three integers.)

Answer 1

Let the middle number be n. That means\[(n-2)+n+(n+2)=42 \implies 3n=42 \implies n=14\]From that, we discern that the three numbers are 12, 14, and 16.

Answer 2

thank u

Answer 3

Can you do a similar problem by yourself now? Do you get it, or did you just trick me into doing your homework?

Answer 4

Three consecutive even integers...
x = 1st integer
x + 2 = 2nd integer
x + 4 = 3rd integer

The three integers equal 42

Lets substitute the three integers in ...
(x) + (x + 2) + (x + 4) = 42 (now combine like terms...)
3x + 6 = 42 (subtract both sides by 6 to get 3x by itself)
3x + 6 - 6 = 42 - 6
3x = 42 - 6
3x = 36 (divide by 3 to get x by itself)
3x/3 = 36/3
x = 12

Now you can figure out the other two integers by substitution...
x = 12 (first integer)
x + 2 = 12 + 2 = 14 (second integer)
x + 4 = 12 + 4 = 16 ( third integer)

check...
12 + 14 + 16 = 42
42 = 42 (correct)

ANSWER : The consecutive, even integers are 12, 14, 16

Answer 5

Very comprehensive explanation kelliegirl33!!

Answer 6

not a problem...just trying to help