Find the area of the shaded portion of the figure. Dimensions are in feet. Leave your answer in terms of p. The figure is not drawn to scale A. (68-8(pi)ft^2 B. (72-16(pi)ft^2 C. (68-16(pi)ft^2 D. None of these
the shaded area = area of trapezoid - area of circle
C. The area of the shaded section would be the area of the (I assume trapezoid) - the area of the circle. (\[b1+b2\div2\])*h = (17/2) * 8 = 68 circle area = pir^2 = 4^2pi = 16pi
wait , im confused , how did you figure that out?
You step back from the problem and see how to arrive at the answer. If the area of the trapezoid is that whole inside part and we subtract the extra stuff in the middle (circle) we get the shaded portion.
maybe, u just undertanding that the diameter of circle = the height of trapezoid
okay , i understand , i looked over what you said and plugged in and got what you was saying, thanks! :)
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