Question

3 sqrt 56x ^14

simplify !

Answer 1

3 sqrt (56x^14)
3 sqrt (2^3 *7 (x^4)^3 *x^2 )
2x^4 (3 sqrt (7x^2) )

Answer 2

If I read the question properly

Answer 3

i think its \(\huge \sqrt[3]{56x^{14}}\) ??

Answer 4

Thats what i took it as hartn

Answer 5

yes it's that hartnn

Answer 6

Or easier to understand if you write it as ((56)(x^14))^1/3

Answer 7

How would you simplify it though..?

Answer 8

well try separate the terms, Leaves you with (56^1/3) and x^14)^1/3.. if you remember the rules of exponents, x^14)^1/3 is simply x^ ( 14*1/3), and 56 is is an irrational number, so you can leave it as (56)^1/3

Answer 9

oh that's it?

Answer 10

or, you go further and say 56)^1/3= 2*(7^(1/3)) (since 8 cube root is 2)

Answer 11

so in the end it would be \[2 \sqrt[3]{7}x^{14/3}\]

Answer 12

thank you very much