Expand using de Moivre’s theorem:
(cosθ + i sinθ )^5

_ nvm, totally forgot the proper context of de moivre's theorem, answer is simply cos(5x) + i sin (5x).

Last part was show that sin (5θ) = 16sin^5 θ − 20sin^3 θ + 5sinθ. How were they able to get the answer in sin only form?

Question

Expand using de Moivre’s theorem:
 (cosθ + i sinθ )^5

>_> nvm, totally forgot the proper context of de moivre's theorem, answer is simply cos(5x) + i sin (5x).

Last part was show that sin (5θ) = 16sin^5 θ − 20sin^3 θ + 5sinθ. How were they able to get the answer in sin only form?

anonymous · Answer

hmmn was easier then i first thought, a lot of tedius work to get sin(5x) in the correct form