Question

Find the angle θ (if it exists) in the interval [0°, 90°) for which sin θ = cos θ

Answer 1

sin θ = cos θ
sin θ = sin(90-θ), so
θ = 90-θ, solve for θ ?

Answer 2

it doesnt say. it just gives me
a. θ = 30°

b.θ = 45°

c. No such angle exists.

d. θ = 60°

Answer 3

yeah, it's just algebra principle...
btw, i have used identity cos(90-x)=sinx

Answer 4

so what would be the answer

Answer 5

there are other ways as well
--> sin/cos = tan so when is tan = 1

--> use unit circle, find angle where sin =cos

Answer 6

θ = 90-θ, move -θ to left side
θ+θ=90
2θ=90
divided by 2 to both sides gives
θ=90/2=...

Answer 7

oh ok thank you!

Answer 8

apparently they don't want to have to do any work....unfortunately most people on this site will not just give answer without explanation ;)

Answer 9

agreed^ ;)

Answer 10

lol k...