Question

2 logb q +8 logb t
how do you write this as a single logarithm

Answer 1

Put the numbers in front as exponents..

\[\log_{b}q^{2}+\log_{b}t^{8}\]

and then remember that

logb(a)+logb(c)=logb(a*c)

Answer 2

so it would be logb (q^2t^8) for the answer

Answer 3

Yes it would

Answer 4

thank you for helping