I am having an EXTREMELY HARD time trying to learn how to factor trinomial that have a special product. Can someone assist me PLEASE!

Question

saifoo.khan · Answer

Do you have some related problems?

anonymous · Answer

Yes, and thank you for your help. $$12x ^{2}+12x-9$$. I have the part about finding the factors of the first, and last terms. I came up with this:
the factors of 12 are
1,12
12,1
2, 6
6, 2
3, 4
4,3
the factors of 9 are
1,9
9,1
3,3 there is no reverse for this factor
Writing down the (x+ )(x- ) which is the next step.

saifoo.khan · Answer

This video must help you ALOT: http://www.khanacademy.org/math/algebra/polynomials/v/factoring-quadratic-expressions After you see this let me know and i'l guide you! :)

anonymous · Answer

okay I am loading now

saifoo.khan · Answer

Sure.

anonymous · Answer

I cannot load the Adobe flash player the computer is a rental, and for some strange reason I have been having issues all day with trying to install it

hba · Answer

How much does it cost per hour.

anonymous · Answer

I have the combinations for the factors of 12, and 9 
(x+1)(12x-9)
(x-1)(12+9)
(x+9)(12x-1)
(x-9)(12x+1)
(x+3)(12x-3)
(x-3)(12x+3)
What am I supposed to do from here... should I work each combination, and when I do I am not sure how to tell which answer will be correct

saifoo.khan · Answer

try reading this:

saifoo.khan · Answer

First step in your problem:
3(4x^2 + 4x-3)
Now factor the brackets.

3(2x-1)(2x+3)