Question

how do you solve log (3x-5) = 2?

Answer 1

Apply a base 10 exponential to both sides...which gives you

3x-5=10^2

should be easy now

Answer 2

why base 10?

Answer 3

because the log on the left needs to be cancelled out. when its just log and no base its assumed its log base 10

Answer 4

ohh okay

Answer 5

Problem: log (3x-5) = 2

I love the tip my high school algebra teacher gave me, of thinking of logs as "a number to a power". So this problem would be worded as: when 10 is taken to the "2" power, you get 3x - 5; what is x?

So we reword it as:
10^2 = 3x-5
100 = 3x-5
105 = 3x
x = 35

Hope that helps!

Answer 6

thank you everyone!!!!:) big hugggs