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2(r^2+1)=5r
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any idea how to solve this?
Distribute the 2 first
then i get 2r^2+2=5r
Right now get the 5r to the left side and then factor
ok
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2r^2-5r+2=0
i get 2r^2-5r+2=0, but there arent any factors of 2 that add up to 5
When the coefficient of the x^2 isnt 1 you do the number in front of x^2 times the last number and find factors of that so 2*2=4 -4 and -1 could get -5 and also multiply to get 4. 2r^2-4r-r+2=0
(2r-1)(r-2)=0 can you solve from here?
i can solve from here. thank you for your help!
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