Find the length of the midsegment? (I already have the answer, I need it checked)
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is it a right triangle?
It looks like it but my question doesnt say anything about that
there's no right angle sign so no
It doesn't need to be a right triangle. It's a question on proportions dealing with similar triangles. 6x + 4 = (1/2)(4x + 56) So, first, solve for "x".
This equality comes from the 2 horizontal lines being parallel and bisecting the 2 sides of a triangle. Notice how they do so halfway down.
Once you solve for "x", you can get your midsegment by just plugging that "x" back into 6x + 4
I started solving the equation and ended up at the end with 10x = 26 which isnt right
how do i find x im failing at it over and over
6x + 4 = (1/2)(4x + 56) -> 6x + 4 = 2x + 28 4x = 24 -> x = 6 So, now, substitute back in.
= 16
thats not one of my options
icalibear, you're just punching in numbers arbitrarily. Show us your work as you answer like tcarroll did and then we can tell you where or if you made a mistake.
6x + 4 = (1/2)(4x + 56) 6x + 4 = 2x + 28 4x + 4 = 28 4x = 24 x = 6 6(6) + 4 = 16
I already gave you: x = 6 All you have to do is: 6(6) + 4 for your answer. You have almost no work left to do.
I got 16 as shown above. But that's not one of my options. So what do I do next?
What is (6)(6) ?
oh 16.i was thinking 12. i dont know why,
36*
not 16
Can you calculate (6)(6) + 4 for your correct answer?
its 40 i was just adding instead of multiplying for some reason
thats where i went wrong lol thanks for helping :P
np You're welcome
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