Question

MsinBt+NcosBt=sqareroot(M^2+N^2) sin(Bt+C)

Answer 1

whats to be done ?
do u need to find C in terms of M and N ?

Answer 2

I need to establish a transformation identity where C is any angle (in radians) and it has (M,N) be a point on it's terminal side.

Answer 3

I was thinking of dividing he right side so that it looks like this:
squareroot(M^2+N^2)/squareroot(M^2+N^2)8(MsinBt+NcosBT)

Answer 4

it is a consequence of the addition angle formula

Answer 5

a short explanation can be found on the attached file

Answer 6

okay thank you

Answer 7

can someone please help me work this out? It's for my own benifit. I am finished with my trig class but just want to work some problems so that I can practice.