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Expand the logarithmic expression log(8) a/2
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\[\frac{ \log \frac{ a }{ 2 } }{ \log8 } + a^6\]
Series expansion @ a = 0
The expansion is different when a = ∞
I think she just want to write that into two logarithm expression, and not the expansion as we know in calculus... am I right? D:
right like log(8)2 -log (log8)
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Then use this awesome formula :D\[\large \log_c\frac{a}{b}=\log_c a-\log_cb\]
\[\large \log_8 \frac{a}{2}=\log_8?-\log_8?\]
=log (8)a-log(8)2
Yup, you got it :)
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