Question

divide and simplify Please help will do the problem on the equation so it looks better

Answer 1

\[\frac{ 2x ^{2}-6x }{ 5x-1 }\div \frac{ x-3 }{ 5x-1 }\]

Answer 2

Ok, that equals:\[\frac{ 2x(x - 3) }{ 5x - 1 } \times \frac{ 5x - 1 }{ x - 3 }\]The 5x - 1 factor and the x - 3 factor will cancel, so your answer will be left as:

2x

And that's it!

Answer 3

thanks tcarroll you are awesome, how do you make it look so simple?

Answer 4

can you help me with some more please

Answer 5

I'm just lucky. Students like you are awesome to work with!

Answer 6

Sure, if I can help, I will!

Answer 7

how about this one
\[\frac{ 16a ^{2} }{4a+9b}-\frac{ 81b ^{2} }{ 4a+9b}\]

Answer 8

I like how people take you step by step for me to understand instead of writing the answer and not letting me know how they got it.

Answer 9

would you divide the 16 by 4 and the 81 by 9

Answer 10

\[\frac{ 16a ^{2} - 81b ^{2} }{ 4a + 9b } = \frac{ (4a + 9b) \times (4a - 9b) }{ 4a + 9b }\]which equals:

4a - 9b

because we have another canceling of a common term in both the numerator and the denominator

Answer 11

That common factor was 4a + 9b which cancels out, leaving as an answer:

4a - 9b

And I'm glad you recognize that I try to give explanations. That means that you are a good, hard-working student who wants to learn. That is very commendable because too many students here just want answers and sadly, they will not learn that way.

Answer 12

i had 4a+9b but now I see how you got the 4a-9b. k please hold on

Answer 13

ok next question is LCM(least common multiple)
x^2+7x,x^2-7x

Answer 14

would it b 7

Answer 15

no holf on it would be 0

Answer 16

Ok, the key to LCM problems is first to factor what you have. So, what you really have to start out with is:

x(x + 7) and x(x - 7)

So, you have to include as factors:

x, x + 7, and x - 7

So, your answer is:

x(x + 7)(x - 7) which is x^3 - 49x or x(x^2 - 49)

You only need one "x" because each term has an "x" in it.

Answer 17

After I asked you if it was 7 or 0 I remeber that I had a problem like this written down from the past I cam up with x(x^2-49)

Answer 18

Yes, that's good that you independently came up with the right answer! That matches mine and you got it right. Good job!

Answer 19

ok here is another one, I wish that I could get the concepts of these a lot easier like you do here is a new one that i have to simplify expression to lowest term and then leave in factor form

\[\frac{ 3y }{ y(4y-1) }+\frac{ 2 }{ 4y-1}\]

Answer 20

Ok, and nice working with you, but I only have time for this last one.\[\frac{ 3 }{ 4y - 1 } + \frac{ 2 }{ 4y - 1 } = \frac{ 5 }{ 4y - 1 }\]Notice how the "y" canceled out of the first term before we added them.

Answer 21

yes and I got 5/4y-1 is that the correct answer

Answer 22

Yes, you are getting these well! Good work and it was very nice working with you!

Answer 23

you too thanks so much I am doing my final and wanting to make sure that I am doing it correctly. This is my last class for my aa, I have a a in this class but I just want to make sure that I am doing everything right before I answer thanks so much again

Answer 24

You'll do well because you are a good student and a nice person. Both count.