Question

I need help
tanx+secx=1

Answer 1

I started with
\[\tan x +\sec x -1=0\]
\[\tan x+\frac{ 1 }{ \cos x }-1=0\]
\[\frac{ \sin x }{ \cos x }+\frac{ 1 }{ \cos x }-1=0\]
\[\frac{ \sin x+1 }{ \cos x }-1=0\]
\[\frac{ \sin x+1 }{ \cos x }-\frac{ \cos x }{ \cos x }=0\]
\[\frac{ \sin x+1-\cos x }{ \cos x }=0\]

What do I do now or where did I go wrong?

Answer 2

Original question was
\[\tan x +\sec x =1\]